ЗАДАЧИ ПО МАТЕМАТИКА! МОЛЯ ПОМОГНЕТЕ

[siselal]

Моля някой да ми помогне да реша задачи 1 б,г .. 2 а ... 4 д, е ..
http://picbg.net/img.php?file=71a194dff2d6be9d.jpg

[Chacho]

1б: 6(1/2+1/3) -2(4/3+3/4) = 6(3/6+2/6)-2(16/12+9/12)=6.5/6 - 2.25/12 = 30/6 - 25/6 = 5/6
не
1г: (14: (1/2+1/3-1/4)) / ((6.10/3-(11/2).(27/11)).3/13) = (14: (7/12)) / ((20-27/2).3/13) = (14.12/7) / ((13/2).(3/13)) = 24 / (3/2) = 16
да

2зад
3((-1)-1)(2.(-1)+2)=3.(-2).0 = 0

4зад
д) а²+b²+2ab-2a-2b = (a²+2ab+b²) - (2a+2b) = (a+b)² - 2(a+b) = (a+b)(a+b-2)
e) x²-4x+3 = x²-x-3x+3 = x(x-1)-3(x-1) = (x-1)(x-3)

[siselal]

mersi mnogo!! )